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Offline PlayingOutpost0-24

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« Reply #125 on: December 03, 2004, 04:35:52 PM »
of course































not!
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Offline CK9

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« Reply #126 on: December 03, 2004, 05:47:43 PM »
if you take an apple and multiply it by pi, then do you have a nice dessert?
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xfir

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« Reply #127 on: December 03, 2004, 10:50:24 PM »
Did I pass chem?
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Offline CK9

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« Reply #128 on: December 04, 2004, 01:19:52 PM »
here, x, I'll test you to see:

true or false

N + I = 2NI
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Offline PlayingOutpost0-24

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« Reply #129 on: December 04, 2004, 05:28:01 PM »
Quote
if you take an apple and multiply it by pi, then do you have a nice dessert?


of course not. you need to multiply the apple at least by pi^7.



btw ck u can contact me bout op3 2...
« Last Edit: December 04, 2004, 05:31:57 PM by PlayingOutpost0-24 »
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Offline CK9

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« Reply #130 on: December 04, 2004, 05:58:50 PM »
lol, how many OP3's are there?

I need to get into monthly contact with everyone making one of the OP games, and I need to get people to help me gather info
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xfir

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« Reply #131 on: December 04, 2004, 07:05:11 PM »
False. Starting with 2 mols and ending with 4 is incorrect. Nitrogen and Iodine don't usually are diatomic.

lol

Hold on.. lemme get a calc problem up.

« Last Edit: December 04, 2004, 07:06:54 PM by xfir »
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Offline CK9

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« Reply #132 on: December 04, 2004, 09:52:15 PM »
*checks chem work*  you're grammer needs some work there... anyway, I think you were trying to say that N and I are both diatomic, which of course is correct, lol.  Unfortunately, you are basing it too much on math.  1 mole each of two non-diatomic elements, when they combine, becomes 1 mole of the molecule created.  With N and I, they can only go 1 atom with 1 atom, and thus 2 moles of NI are created

luckily, we just covered that type of problem in calc:

[(x^6)/6 - (3x^2)/2 + 7x]4 5 = (((4)^6)/6 - (3(4)^2)/2 + 7(4)) - ((5^6)/6 - (3(5)^2)/2 + 7(5)) = (682.67 - 24 + 28) - (2604.17 - 37.5 + 35) = (686.67) - (2601.67) = -1915
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Offline plymoth45

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« Reply #133 on: December 05, 2004, 03:12:24 AM »
ok, the x^5 -3x+7 i can understand, but what the hell is that other thing?
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xfir

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« Reply #134 on: December 05, 2004, 05:02:46 PM »
The Integration sign!

It's calc.. you will eventually learn it.. I'm taking Calc 2 next semester, so that shall be fun.

I may make some more problems later on.

As for CK9, he did excellent. He took the Antideriative and solved using that.. now I will go make another problem that you can't easily take the antideriative of. Later.. much so..
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Offline CK9

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« Reply #135 on: December 15, 2004, 09:41:07 PM »
X, I know several ways to solve the problem, but you need to study chem a little more :P
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Offline Hooman

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« Reply #136 on: December 15, 2004, 11:34:42 PM »
Ahh, are you guys really sure about that chem answer? I would get this.

N[size=8]2[/size] + 3I[size=8]2[/size] = 2NI[size=8]3[/size]

Granted, they both form diatomic molecules, but they bond differently. Nitrogen would form a tripple bond since it's missing 3 electrons in it's valence shell. Iodine will only form a single bond since it's missing 1 electron in it's valence shell. Thus it'll take 3 iodine atoms to bond with each nitrogen atom to form a stable molecule.


Hmm..., how about

Integral( x = 1..2, 1/(x^2+x-2))
« Last Edit: December 15, 2004, 11:36:19 PM by Hooman »
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Offline jesusfreak06

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« Reply #137 on: December 16, 2004, 08:11:19 AM »
just when i thought that i was done w/ chem... wow, i don't remember anything from it... (that could b a good thing).  
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Offline CK9

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« Reply #138 on: December 16, 2004, 08:30:56 AM »
Quote
Hmm..., how about

Integral( x = 1..2, 1/(x^2+x-2))
I've never seen it lain out like that, but I'll try:

./.2
.|............1........ dx
.|....x^2 + x - 2
/..1

heck, I don't even have to continue, it equals infinity.  Also, if the 2 and 1 are switched, then it equals negative infinity
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Offline PlayingOutpost0-24

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« Reply #139 on: December 16, 2004, 02:18:20 PM »
oh sigh... i had enough with chem...

P3H2O7N5E4
« Last Edit: December 16, 2004, 02:18:46 PM by PlayingOutpost0-24 »
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Offline CK9

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« Reply #140 on: December 16, 2004, 05:16:23 PM »
lol. there's no element with E as the symbol :P (I'm being weird)
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xfir

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« Reply #141 on: December 17, 2004, 12:57:44 AM »
Quote
Quote
Hmm..., how about

Integral( x = 1..2, 1/(x^2+x-2))
I've never seen it lain out like that, but I'll try:

./.2
.|............1........ dx
.|....x^2 + x - 2
/..1

heck, I don't even have to continue, it equals infinity.  Also, if the 2 and 1 are switched, then it equals negative infinity
Where'd you get the basis that it would equal infinity?

I'd say it would be closer to 0 than infinity.

I don't have my Calc book with me, or I would try to solve that.
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Offline CK9

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« Reply #142 on: December 17, 2004, 08:48:37 AM »
think about it for a while x, you'll see tat it is infinity
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Offline zeritou

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« Reply #143 on: December 17, 2004, 10:05:00 AM »
i liked chem

(ill try my hand at ascii art, is usually doesnt work for me in this forum)

    Fe-------Fe
   /  \        /   \
Fe--Fe----Fe--Fe
 |     |     |     |
Fe--Fe----Fe--Fe
   \  /       \    /
    Fe-------Fe


i know its slightly out of proportion especially if my ascii skills suck but what is the name of the molecule i just drew

edit: added anser: its a ferrous wheel
« Last Edit: January 13, 2005, 09:57:33 AM by zeritou »
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Offline Hooman

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« Reply #144 on: December 17, 2004, 01:45:26 PM »
Quote
it is infinity

Correct. It was a divergent integral. (I actually just picked the interval of integration quite arbitrarily and didn't notice when I posted this. But it's still about the same level of difficulty. Only slightly harder than I intented. Actually the problem was that I was fussing over the denominator and accidentally made a root at 1.)


Well, ok. A slightly easier question then. Same thing but different interval of integration.

Intregral( x = 2..3, 1/(x^2+x-2))


And yes, I actually worked this one out.  :blush:
« Last Edit: December 17, 2004, 01:46:03 PM by Hooman »
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Offline CK9

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« Reply #145 on: December 17, 2004, 06:16:04 PM »
./.3
.|............1........ dx
.|....x^2 + x - 2
/..2

let's seee... that would be about .1567
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xfir

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« Reply #146 on: December 17, 2004, 09:37:45 PM »
Naw, at this point, I stopped thinking. :)

I got a B in Calc I, so I don't have to think about math for the next 2 weeks or so.
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Offline Hooman

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« Reply #147 on: December 17, 2004, 10:26:19 PM »
zeritou: I have no idea. Unless it's a simple answer like Fe12 or something like that.

CK9, yeah ok, but what's the exact answer? Numerical integration doesn't count.  ;)

Besides, if I'd been marking a quiz that just stated the answer like that, I'd be tempted to give it something like 1/5. Anyways, the question should be about a Calc II level.
 
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Offline CK9

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« Reply #148 on: December 18, 2004, 12:23:50 PM »
lol, I'm in my first year of Calc, though

What do you mean by exact answer?  If I were to give the initial answer, it would involve ln, and I hate leaving that operation in the answer
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Offline Hooman

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« Reply #149 on: December 18, 2004, 02:16:59 PM »
People always leave things like ln in their final answer. It's exact. Besides who uses a calculator anyways?
« Last Edit: December 18, 2004, 02:18:23 PM by Hooman »
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